Feedback, and the margin

What the load sees looking back

Four rungs of this argument have measured what the amplifier does to the signal — the margin, the settling, the error, the noise. None has asked the question from the other end. A load that draws its own current sees an impedance looking back, and with the feedback taken from the amplifier that impedance is the isolation resistor, with no loop gain in it whatever: ten ohms, and a load step leaves an error that never goes away. The two-path arrangement recovers to a thousandth of it and charges for that in a quantity none of the four rungs below measured.

Assumes: The load that gets inside the loop · What is left at crossover · How much of the amplifier gets through

This is the fifth rung of one argument, and the first four all asked the same kind of question. An amplifier drives a capacitive load; the load eats its margin; a resistor in series buys the margin back and costs the regulation; a second feedback path buys the regulation back and puts a doublet in the settling; and the doublet turns out to cost nothing at the noise floor. Margin, settling, error, noise.

Every one of those is a measurement of what the amplifier does to the signal. None of them is a measurement of what the load has.

A load is not a capacitor sitting quietly. It is something that draws current — a logic input that switches, a converter that samples, a stage whose bias steps — and what decides how far the node moves when it does is not the loop gain but the impedance it is looking back into. That impedance is what this essay measures, and it separates the three arrangements in a way none of the four rungs below could.

The load sees 10.0 Ω, 1.2e-3 Ω or 1.2e-3 Ω at direct current, and the peak is lowest for the arrangement with both paths. computed by solving, not by drawing. The impedance at the load node of all three arrangements, measured by grounding the input and driving a unit current into the load. Feedback from the amplifier leaves the load looking at the isolation resistor — 10.0 Ω, with no loop gain in it at all. Feedback from the load gives 1.2e-3 Ω, and the two-path arrangement has the same, which is what its direct-current path is for. All three resonate with the load capacitance near 3.2 MHz, and the two-path arrangement's peak is the lowest — 27.6 Ω against 37.4 and 59.2. What it gives up is between: above the 159 kHz handover it has let go of the load node.
Fig. 1 The impedance at the load node of all three arrangements, measured by grounding the input and driving a unit current into the load. Three curves that agree at high frequency and are four orders apart at low.

The measurement, which is the site’s usual one pointed the other way

Ground the input. Put a one-ampere current source into the load node. Read the voltage there. That is what “the impedance the arrangement presents to the load” means when it is measured rather than argued about, and it is the same operation this collection uses for every impedance it draws.

One decision inside it is worth stating because the opposite decision would be defensible and wrong. The load capacitance stays in place. It is part of what the load sees; removing it would measure a circuit nobody has, and the entire subject of this anchor is that the capacitor is there.

Impedance of a series RLC of Q = 4, measured by driving it. One ampere is forced into the terminals at each frequency and the resulting voltage is the impedance. The minimum is 7.91 Ω at 5.03 kHz.
Fig. 2 The general form, from the frequency field: an impedance driven with a current and read as a voltage, which is the only definition that survives contact with a network that has feedback in it.

Ten ohms, with no loop gain in it at all

The first result is the one that makes the essay necessary.

With the feedback taken from the amplifier’s own output — the second rung’s arrangement, the one that buys the margin back — the impedance at the load node at direct current is 10.00 ohms. That is the isolation resistor, to four figures, and there is no loop gain in it anywhere.

The reason is structural and is the whole of the second rung’s compromise stated in a new quantity. The loop regulates the node it is fed back from, and it is fed back from the amplifier’s output. The isolation resistor is outside the loop, so what the load is connected to is a regulated node with an unregulated resistor in series, and a hundred decibels of loop gain does not reach past it.

With the feedback taken from the load instead, the same measurement gives 1.2 milliohms — four orders lower, because now the loop is regulating the node the load is on. And the two-path arrangement, which takes its direct current from the load and its fast path from the amplifier, gives 1.2 milliohms as well. It has the good number, exactly.

9.9 Ω restores 45°, 23 Ω restores 60°, and the load pays for it in ohms. computed by solving, not by drawing. Phase margin against the resistor placed between a unity-gain inverter's output and 2.2 nF of load capacitance, with the feedback taken from the amplifier's own side of it. With no resistor the margin is 30.11°; 9.90 Ω restores 45° and 23.20 Ω restores 60°. The lower curve is the same resistor with the feedback taken from the load instead, where it makes every value worse — the pole is then inside the loop rather than outside it, and at 220 Ω the margin is 13.4°. The rising curve is what it costs: the loop no longer regulates the load's node, so 1 kΩ of resistive load pulls the output down by 0.990% at 10 Ω, uncorrected, at direct current.
Fig. 3 The arrangement that produces the ten ohms, from the rung below: an isolation resistor restores the margin and takes the load node out of the loop.

What a load step actually does

The impedance curve says everything about this in principle and nothing in practice, because what a designer has is not a swept current source but a load that switches on. Marching a one-milliamp step forward in time turns the curve into the two numbers a designer has:

arrangement left after it settles excursion back within 2%
feedback from the amplifier 10.00 mV, permanently 23.6 mV 0.62 µs
feedback from the load 1.2 µV 21.1 mV 1.00 µs
both paths 1.2 µV 19.6 mV 0.30 µs

The first row is the finding restated in the currency of a data sheet. A milliamp of load current leaves ten millivolts of error at the load for ever — not while it settles, not until the loop catches up, permanently — because the isolation resistor is a resistor and the loop cannot see it. On a one-volt signal that is one per cent, and it is the same one per cent the third rung of this argument measured as a direct-current regulation error, arriving here through a completely different door.

Both paths recover to 1.2 µV of a 10.0 mV error that never goes away. computed by solving, not by drawing. The voltage at the load node of all three arrangements after a 1 mA step of load current, marched forward in time. The amplifier-feedback arrangement settles to 10.0 mV and stays there — the isolation resistor is outside the loop, so that error is permanent. Both the load-feedback and the two-path arrangements come back to 1.20 µV. The two-path arrangement's excursion is the smallest of the three at 19.6 mV, and it takes 0.30 µs to get back against 0.62 and 1.00 — a time set by the handover between its two feedback paths, whose own constant here is 0.12 µs, and which moves with the compensation capacitor rather than being a property of the arrangement.
Fig. 4 The three arrangements answering a one-milliamp step of load current, marched forward in time. Two of them come back; one of them settles ten millivolts away and stays there.

The march and the impedance curve share no arithmetic — one is a trapezoidal integration of the netlist in time and the other a solve at s=0s = 0 — and they agree on where each trace ends to better than three per cent of the excursion. That agreement is the check that neither is measuring itself.

Where the cost is, and it is not where the last two rungs found theirs

The fourth rung asked whether the second feedback path costs anything at the noise floor and found that it does not. This rung asks whether it costs anything at the load and finds that it does — in a quantity neither of the two rungs below had a reason to look at.

It is not the excursion. The two-path arrangement’s is the smallest of the three, 19.6 mV against 23.6 and 21.1.

It is not the resonant peak. All three arrangements ring against the load capacitance somewhere above a megahertz, and at 2.2 nF the two-path arrangement’s peak is 28 Ω against the amplifier path’s 37 and the load path’s 59 — again the best of the three.

One number in this section is at a different compensation from the ones above it, and it is worth saying which. The impedance curves are drawn at 100 pF, because the band in which the two-path arrangement has let go of the load node and has not yet resonated only exists there: at the settling optimum of 12 pF the handover is at 1.33 MHz and the resonance is at 2.6, so the two run into each other and there is no middle. The load-step measurements are at the settling optimum, which is the capacitor a designer would actually fit.

It is the time. With the compensation capacitor at 100 pF the two-path arrangement takes 3.38 µs to get back inside two per cent of its excursion, against 0.62 for the amplifier path and 1.00 for the load path. At 220 pF it takes 7.31 µs.

And the mechanism is one this argument has met before, from the other side. The handover between the two feedback paths puts a pole and a zero close together — a doublet — and a doublet is invisible in a margin, nearly invisible in a magnitude, and decisive in a recovery. The third rung of this anchor found exactly that in the signal path. Here it is in the load path, with the same cause and a different victim.

Both paths recover to 1.2 µV of a 10.0 mV error that never goes away. computed by solving, not by drawing. The voltage at the load node of all three arrangements after a 1 mA step of load current, marched forward in time. The amplifier-feedback arrangement settles to 10.0 mV and stays there — the isolation resistor is outside the loop, so that error is permanent. Both the load-feedback and the two-path arrangements come back to 1.20 µV. The two-path arrangement's excursion is the smallest of the three at 19.0 mV, and it takes 7.31 µs to get back against 0.62 and 1.00 — a time set by the handover between its two feedback paths, whose own constant here is 2.20 µs, and which moves with the compensation capacitor rather than being a property of the arrangement.
Fig. 5 The same three arrangements with the compensation capacitor at 220 picofarads, where the two-path arrangement’s tail is 7.31 µs. The tail is the handover’s own time constant, so it is a design number rather than a property of the arrangement.

The third quantity the same capacitor decides

That last sentence is what makes this rung worth the fifth place, because the compensation capacitor now decides three things and the rung below already found that two of them disagree.

Swept from 1 pF to 220, the load-step recovery has a minimum, and it is at 12 pF — which is exactly the capacitor the third rung found settles the signal fastest. The two agree, and they agree to the value on the slider rather than approximately.

The fourth rung found that the capacitor which is quietest is eighteen times that one. At 220 pF the load-step recovery is 7.31 µs against 0.30 — twenty-four times slower.

So the trade the fourth rung named has a third party and the third party takes a side:

  • 12 pF: the fastest signal settling, the fastest load recovery, 61.8° of margin;
  • 220 pF: the lowest total noise at the load, 46.3° of margin, and a load-step recovery twenty-four times longer.

Two of the three quantities prefer the small capacitor decisively and the third prefers the large one. A designer who read only the fourth rung would take the quiet capacitor and would be right unless the load draws current — and the loads that need this compensation, converters and switching stages, are exactly the loads that draw current.

The second path costs nothing at 12 pF and an order at 100 pFcomputed by solving, not by drawing. Settling time to 0.01% of final value, marched on the closed loop, against the value of the second feedback path's capacitor — with the phase margin of the same circuit divided by ten drawn on the same axis so the two can be compared. The direct-current error the previous rung recorded as the isolation resistor's cost, 0.99% into 1 kΩ, falls to 1.20e-4% with the second path in. What the second path costs instead is a range: at 12 pF the circuit settles in 0.745 µs against the isolation resistor's 1.419 µs — faster than the thing it repairs — and at 100 pF it takes 9.18 µs, 12 times longer, at a phase margin of 47.9° that reports nothing whatever about it. What it is settling by there is one exponential of time constant 0.99 µs, which is the feedback network's own RC and contains no amplifier.110110100feedback capacitor from the amplifier output (picofarads)settling to 0.01% (microseconds), and margin ÷ 10 (degrees)the isolation resistor alone: 1.42 µsbest: 12 pFsettling, and the margin that does not predict itload capacitance2.2 nFisolation resistor10 Ωthis capacitor12 pFmargin here61.82°settling to 0.01%0.745 µsbest is0.745 µs at 12 pFresistor alone settles1.419 µs…and its d.c. error0.990%two paths, d.c. error1.20e-4%at 100 pF the tail isτ = 0.993 µssolved, then checked — settling against the second path's capacitora band around 12 pF
Fig. 6 The rung this one is standing on: the settling time and margin against the compensation capacitor, with its own minimum at 12 pF. Drag it — the number this essay’s recovery sweep independently arrives at.
Both paths recover to 1.2 µV of a 10.0 mV error that never goes away. computed by solving, not by drawing. The voltage at the load node of all three arrangements after a 1 mA step of load current, marched forward in time. The amplifier-feedback arrangement settles to 10.0 mV and stays there — the isolation resistor is outside the loop, so that error is permanent. Both the load-feedback and the two-path arrangements come back to 1.20 µV. The two-path arrangement's excursion is the smallest of the three at 19.2 mV, and it takes 1.63 µs to get back against 0.62 and 1.00 — a time set by the handover between its two feedback paths, whose own constant here is 0.47 µs, and which moves with the compensation capacitor rather than being a property of the arrangement.
Fig. 7 The third quantity the same capacitor decides: the load step, at forty-seven picofarads. The impedance the load sees, the settling of the main signal path and the recovery from a load step are three readings of one compensation capacitor, and they do not have the same optimum.

The peak, and the inductance nobody put in the circuit

One feature of the impedance curves deserves its own paragraph because it is the same object this field has met twice under other names.

Between direct current and about a megahertz, the impedance of the load-feedback arrangement rises in proportion to frequency. A magnitude proportional to frequency is an inductance, and there is no inductor anywhere in the netlist. What produces it is the loop gain falling: the output impedance is roughly the amplifier’s own output resistance divided by the loop gain, the loop gain falls as one over frequency above the dominant pole, so the quotient rises as frequency.

That synthetic inductance then resonates with the load capacitance, which is where every one of these curves peaks, and the peak is what an ordinary load sees as ringing.

The load capacitance moves the peak and does not remove it. At 0.22 nF all three peak near 53–60 Ω; at 22 nF the peaks are 12–55 Ω and the ordering of two of them has swapped, because the synthetic inductance is a property of the amplifier and the capacitance is not.

The load sees 10.0 Ω, 1.2e-3 Ω or 1.2e-3 Ω at direct current, and the peak is lowest for the arrangement with both paths. computed by solving, not by drawing. The impedance at the load node of all three arrangements, measured by grounding the input and driving a unit current into the load. Feedback from the amplifier leaves the load looking at the isolation resistor — 10.0 Ω, with no loop gain in it at all. Feedback from the load gives 1.2e-3 Ω, and the two-path arrangement has the same, which is what its direct-current path is for. All three resonate with the load capacitance near 0.4 MHz, and the two-path arrangement's peak is the lowest — 12.8 Ω against 12.0 and 54.6. What it gives up is between: above the 159 kHz handover it has let go of the load node.
Fig. 8 Ten times the load capacitance. The two-path arrangement’s peak is no longer the lowest of the three — the amplifier-feedback one’s is, by a hair — which is why that comparison is a claim about the slider rather than about the arrangement.

Why this is a rung and not an aside

This collection counts depth in rungs against an idea, and five is further than any argument here has gone. It is worth saying what makes this a fifth rung rather than a fifth figure, because the test is not “another measurement of the same circuit”.

The four rungs below all treat the amplifier as the thing being studied and the load as a condition imposed on it — a capacitance to be tolerated. Each of them asks what the capacitor does to a quantity belonging to the amplifier. That is a coherent way to think about the problem and it is the way every data sheet and every application note thinks about it, and it has a blind spot with a shape: any quantity belonging to the load is invisible from inside it.

The ten ohms is in that blind spot. It is not a degradation of anything the four rungs measured. The margin is fine, the settling is fine, the noise is fine, the direct-current error of the signal was measured and repaired two rungs ago — and a load that draws a milliamp still sits ten millivolts away from where the amplifier thinks it is, permanently, and nothing in the four rungs below reports it.

That is the shape of finding this collection exists for, and it is the same shape as the recovery loss that turned out to be in the switch rather than in the diode, or the noise that folds as many times as the settling needs time constants: the quantity is not wrong, it is being attributed to the wrong component.

Where a load resistance sits in all of this

Every number above is for a load that draws its current in steps and has no steady resistance. A real load usually has both, and the arithmetic for the steady part is worth one paragraph because it is where the ten ohms turns from a curiosity into a specification.

A load resistance and the output impedance form a divider. With the feedback from the amplifier, the gain to the load node is divided by 1+Riso/RL1 + R_\mathrm{iso}/R_L — one per cent into a kilohm, which is the number the resistor that buys the margin back measured directly and called a regulation error. Here it is the same ten ohms wearing its other hat: as a series resistance it divides a steady signal, and as an output impedance it converts a load current into an error. One component, two symptoms, and a designer who fixes the first by calibration still has the second.

This is also where the arrangement stops resembling a regulator, which is the circuit a reader is most likely to have in mind. A source below a frequency measures a regulator’s output impedance and finds 0.43 milliohms at direct current, because there the loop is closed around the output node itself and nothing sits between the two. The isolation resistor here is what a regulator does not have, and its cost is the four orders of magnitude between those two numbers.

The two-path arrangement removes both at once, and that is the cleanest statement of what its direct-current path is for. The path that buys the error back is where its price is established, and the price is a range rather than a number: a settling time running from 0.745 microseconds to 9.18 across the load capacitances the design has to cover, with the phase margin at the slow end being the better of the two. It does not reduce the isolation resistor’s value, improve its tolerance or move it inside the loop in any physical sense; it gives the loop a second look at the node the resistor is on, at frequencies where looking is safe.

The three quantities one capacitor decides

The compensation capacitor on this page decides three things and they do not share an optimum. This one is the impedance the load sees. The path that buys the error back is the settling of the signal path, whose fastest value and best margin are different components. What the second path costs at the floor is the noise, whose optimum is eighteen times away from the fastest settling. The load that gets inside the loop is the problem all three are answers to, and The buffer that is not a buffer is the same inductive output impedance one field over, without a loop around it.

What is checked

The direct-current impedance of the amplifier-feedback arrangement is asserted to be the isolation resistor to two per cent, which is the claim that the loop does not reach the load at all. The other two are asserted to be a thousandth of it, and the two-path arrangement’s is asserted to equal the load-feedback one’s to five per cent — the three assertions that between them say which arrangement has which number and why.

The two routes are required to agree: every marched trace must arrive within three per cent of its excursion at the value a solve at s=0s = 0 predicts. They share no arithmetic, and the two-path arrangement’s tail is long enough that reading the end of the march instead would have reported a settling time against a moving target — which is what a first version did.

The two-path arrangement’s resonant peak is asserted to be below the load-feedback arrangement’s, which holds at every load capacitance on the slider. That it is below the amplifier-feedback one’s as well holds at small capacitance and not at large, so it is a claim about the sweep and lives in the site’s gate.

The recovery time is asserted to be of the order of the handover’s own time constant rather than against a number, because the whole point is that it moves with the compensation capacitor. That its minimum over the capacitor coincides with the settling optimum, and that the quiet capacitor is twenty-four times slower to recover, are claims across settings and are in the gate too.

What is not measured: a load that draws current and has capacitance of its own, which is most real loads and would move the resonance rather than only exciting it; the amplifier’s own supply rejection, so every number here assumes the rail does not move when the load steps; and a load step large enough to slew the amplifier, at which point none of this is linear and the impedance stops being a quantity.

The second and third of those are the two rungs above this one, and both turn out to be larger than the sentence above suggests. The step too large to have an impedance locates where the third begins and finds it low: give the amplifier the differential pair’s own tanh in place of a linear transconductor and the ratio of voltage to current is a number up to 10.6 milliamps and not above, where the input error is 3.63 thermal voltages and the slew rate deciding it is twice the thermal voltage times the gain–bandwidth in radians — an expression with no design choice in it at all. The rail the load moves removes the second assumption and finds something the sentence above could not have predicted: giving the rail an impedance changes this channel’s own output impedance by three parts in ten million, because the loop corrects the supply along with everything else, and instead opens a path to a second amplifier that shares nothing with this one but a wire. How large that path is is a modelling choice rather than a measurement — 3.84 microvolts per ampere with the compensation capacitor returned to ground, 17.3 millivolts with it returned to the rail, a factor of four and a half thousand.

So of the three omissions named here, the one that mattered was not the one that looked largest. The supply was expected to be a small correction to this measurement and is; what it was not expected to be is a coupling to a circuit that is not in the netlist.

Part 5 on capacitive load

One argument about Capacitive load, and one of 10 essays on it so far, each part numbered by how much of the idea it assumes. What sits either side of it:

What links here

Essays that reach for this one mid-argument — the half of a link its own author cannot write down, the 8 sharing most with it of 9.

The objects named here

The third axis, after the field and the idea: the things themselves, and every essay that touches each one.

Capacitive loadDesign tradeoffDoubletLoadingLoop gainModel rangeOutput impedanceSettling time